100x^2-240x+128=0

Solution for 100x^2-240x+128=0 equation:

100x^2-240x+128=0

a = 100; b = -240; c = +128;
Δ = b2-4ac
Δ = -2402-4·100·128
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-80}{2*100}=\frac{160}{200}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+80}{2*100}=\frac{320}{200}
=1+3/5
$